1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you simplify, the result is:
-10</span><span>±5</span>√2 (It is the last option).<span>
</span>
Any value of x makes this equation true or all real numbers
-2(3x+12) is the same this as -6x-24 when distributed
so it's -6x-24=-24-6x
her -6x just disappeared so she is wrong :)
There isn't anything there
Answer:
x = 3
Step-by-step explanation:
3=5x-12
Rearrange the Equation.
5x - 12 = 3
Add 12 to both sides.
5x - 12 + 12 = 3 + 12
Simplify
5x = 15
Divide both sides by 5
5x/5 = 15/5
x = 3
Answer:
x = 181 and y = 97
Step-by-step explanation:
let called the first number is x
the second number would be called y
We are given that:
x + y = 278 (1)
x = y + 84 (2)
Let change x in (2) into (1):
y + 84 + y = 278
2y + 84 = 278
Subtract 84 from both side, we got:
2y + 84 - 84 = 278 - 84
2y + 0 = 194
Divide both side by 2, we got:
2y / 2 = 194 / 2
y = 97
Because y = 97 and x + y = 278 so x would equal:
x + 97 = 278
Subtract 97 from both side, we got:
x + 97 - 97 = 278 - 97
x + 0 = 181
x = 181 and y = 97
Hope this helped :3
