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il63 [147K]
3 years ago
5

Convert 40 yards to feet

Mathematics
1 answer:
olchik [2.2K]3 years ago
5 0

Answer:

120 feet

.................................

Step-by-step explanation:

1 yard = 3 feet

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Explain why are whole numbers are rational numbers ​
Reptile [31]

Answer:

Every whole number is a rational number: for example, 3=31. So it is rational. Every whole number n can be written as a fraction of integers: n=n1. We aren't required to write it that way; we just need to know that it is possible to express every whole number as a fraction of integers, and hence it is rational.

Step-by-step explanation:

hope this helps

6 0
3 years ago
Read 2 more answers
What is the radical form of each of the given expressions?
Ahat [919]

Answer:

Step-by-step explanation:

These exponential forms can be written into radicals very easily as long as you remember the rule:  The denominator of the rational exponent serves as the index of the radical and the numerator serves as the exponent on the radicand. Let's look at a rational exponent.  3/4  4 would be the index on the radical (the number that sits in the little dip of the radical sign) and 3 is the power on the base.  So

x^{\frac{3}{4}} can be written in radical form as

\sqrt[4]{x^3}

Let's do 3^3/2 in your problem.  2 is the index (which is a "normal" square root and you don't need to write a 2 there cuz it's understood that it's a 2 if nothing is there), and 3 is the power on the base, which in our case is a 3.  Bases can be numbers OR letters.

3^{\frac{3}{2}}=\sqrt[2]{3^3}=\sqrt{3^3}

That does in fact have an actual number answer, but I don't think you are simplifying them yet, only learning to write them from one form to another, so there you go!

5 0
3 years ago
Perform the indicated operations below and simplify ((a+b)/4) + ((2a-b)/5).
ArbitrLikvidat [17]

Answer:

\frac{(a+b)}{4} +\frac{(2a-b)}{5}=\frac{13a}{20} +\frac{b}{20}

Step-by-step explanation:

We have:

\frac{(a+b)}{4} +\frac{(2a-b)}{5}

We can use <em>common denominator</em>.

Observation:

If you have, \frac{a}{b} +\frac{c}{d}=\frac{(a*d)+(c*b)}{b*d}

Then,

\frac{(a+b)}{4} +\frac{(2a-b)}{5}=\frac{5(a+b)+4(2a-b)}{4*5}

Using <em>distributive property</em>:

Observation:

c(a+b)=ca+cb

\frac{5(a+b)+4(2a-b)}{4*5}=\frac{5a+5b+8a-4b}{20}=\frac{(5a+8a)+(5b-4b)}{20}

Finally,

\frac{(5a+8a)+(5b-4b)}{20} =\frac{13a+b}{20}=\frac{13a}{20} +\frac{b}{20}

The answer then is:

\frac{(a+b)}{4} +\frac{(2a-b)}{5}=\frac{13a}{20} +\frac{b}{20}

5 0
3 years ago
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