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Nitella [24]
3 years ago
12

Find the value of 2cosx+1=0;0 less than x less than 360°

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

Answer:

120°; 240°

Step-by-step explanation:

Let's first solve for cosx: 2cosx=-1 \rightarrow cosx=-\frac12 At this point it's just a matter of drawing a circle, and mark where the angle is(please excuse my paint skills, but free hand drawing would be even worse). Red line, is -\frac12 on the cosines, and both the green and blue lines are valid solutions. The green line is a quarter of a circle, plus 30°, or 120°. The blue one is 3/4 of a circle, minus 30 degrees, or 240°.

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What is 17 divided by 3 without remainders.
LenaWriter [7]

Answer:

5.6666666667

Step-by-step explanation:

that is 17 divided by three without remainders

4 0
3 years ago
Read 2 more answers
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
Josh needs to wash 4 plates, 12 pieces of silverware, and 4 cups. Then he needs to dry them all. How many items will he touch, i
geniusboy [140]

Answer:

40 times.

Step-by-step explanation:

4+4+12=(20 x 2)=40

5 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
4 years ago
For the multiple regression model Y with hat on top equals 40 plus 15 X subscript 1 minus 10 X subscript 2 plus 5 X subscript 3,
kvasek [131]

Answer:

When x1 and x2 decrease 4 units, y decreases by 20 units

Step-by-step explanation:

The regression model is

y=40+15x_1-10x_2+5x_3

We have to calculate y for a decrease of 4 units in x1 and x2. For this we have to calculate the variation of y in function of x1 and x2.

As it is a linear regression model, we have:

\Delta y=15\Delta x_1-10\Delta x_2

For a variation in 4 units of x1 and x2, we have

\Delta y=15\Delta x_1-10\Delta x_2\\\\\Delta y=15(-4)-10(-4)=-60+40=-20

6 0
3 years ago
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