1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pentagon [3]
3 years ago
9

How does the area of the polygons compare to π? ( π is 3.14)

Mathematics
2 answers:
svp [43]3 years ago
8 0

Answer:

is comares by using the same meathod to slove pi

Step-by-step explanation:

soldi70 [24.7K]3 years ago
5 0

The area of the polygons compare to π in the way that as more angles and sides are added to a polygon the polygon becomes closer to a circle; the perimeter slowly changes to circumference. Π is used to find the area and circumference of a circle, so as polygons come closer to becoming circles π becomes more strongly associated to the polygon. You can even use π to find the approximate area of a circle if you use the same formula (as you would to find the area of a circle) on a polygon. Another way to go about it is like this…

You can find the area of a circle if you know the circle’s circumference by using these steps:

<span>1.         Divide the circumference by π to find the diameter of the circle.</span>

<span>2.         Divide the diameter by 2 to find the radius of the circle.</span>

<span>3.         Now that you have the radius you can use the formula Area= πr2 to find the area of the circle.</span>


You might be interested in
What sentence about markdowns and markups is true?
Eduardwww [97]
The answer is C.
<span>C. A markup has no limit, but a markdown is limited to 100% or less. </span>
8 0
3 years ago
5. Writing to Explain How many 2-inch cubes could fit inside the
kupik [55]
IF SOMEONE PUTS A LINK AS AN ANSWER,DONT GO TO THE LINKS. PEOPLE USE THEM TO FIND YOUR ADDRESS
8 0
3 years ago
What did I do wrong and what is the right answer
11Alexandr11 [23.1K]
The second one u picked is not correct. Plug on the answers for all the options making sure that they match up with the expression in the question
8 0
3 years ago
If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution
FrozenT [24]

Answer:

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of \hat{p} can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

  • np ≥ 10
  • nq ≥ 10

Both of these conditions must be met in order to approximate the sampling distribution of \hat{p} as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This  means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

6 0
3 years ago
What the answer is to question number 4
cestrela7 [59]
Hey there!
The answer is D. 1/5
An explanation is in the attached image below.
Hope this helps!

3 0
2 years ago
Other questions:
  • Write down the 2nd term in the sequence given by : T(n)=n2-2n
    7·1 answer
  • What value represents the horizontal translation from the graph of the parent function f(x) = x2 to the graph of the function
    8·2 answers
  • How much interest would be paid in 1 year for a loan of $3600 at 8 1/2% simple interest?
    10·2 answers
  • Which expression could NOT be used to find the number of square pieces
    5·1 answer
  • What are the possible degrees for the polynomial function?
    13·1 answer
  • Is 5.18 rational or irrational
    7·1 answer
  • Does someone knows what equals 12.5 please
    14·2 answers
  • Help pls I'll give 25 points
    5·1 answer
  • How many solutions does this equation has: 3x-5=-3
    6·1 answer
  • (1 point) If p(x) and (x) are arbitrary polynomials of degree at most 2, then the mapping =p(-1)q(-1) + p(070) +p(3)q(3) defines
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!