With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.
Here
m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by:
L: y-5=-10(x-(-3))
on simplification
L: y=-10x-30+5
L: y=-10x-25
Your equation is correct.
Answer:
A: 22
Step-by-step explanation:
2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.
Answer:
C. 27
Step-by-step explanation:
well we can use the pythagorean theorem for this and disregard the 11. so we have the hypotenuse and one side so therefore a^2+b^2=c^2 and if we plug in the numbers it would look like this
16.5^2+x^2=29^2
272.25+x^2=841
x^2=568.75
and from multiple choice we can infer that the answer is obviously bigger than 16.5 because in the picture x is a longer side but it is smaller than 29 and the only answer in between those two numbers given would be C. 27
