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OLga [1]
3 years ago
7

Which of the following sets are subspaces of R3 ?

Mathematics
1 answer:
Ratling [72]3 years ago
5 0

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

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5. What is the mode in this sequence of numbers? 5, 10, 16, 3, 8, 11, 7, 10,2 I a. 8 b. 5 c. 11 d. 10​
Salsk061 [2.6K]

Answer:

Step-by-step explanation:

c, because 3+8 is 11 so c would be correct

5 0
2 years ago
a molecule is measured and the width is 3x10-6 cm. how long will a string of 225 similar molecule be? give your answer in scient
mixer [17]

The length of the molecule is 6.75*10^-^4cm in scientific notation.

Data;

  • Width of molecule = 3*10^-6 cm
  • Number of molecules = 225

<h3>Length of the molecule</h3>

This can be calculated as the total length of the 225 molecules added together. To do this, we simply multiply both the numbers of the molecules by the width of the molecule.

This becomes;

3*10^-^6*225 = 0.000675cm = 6.75*10^-^4cm

The length of the molecule is 6.75*10^-^4cm in scientific notation.

Learn more on scientific notation here;

brainly.com/question/5756316

brainly.com/question/1712028

7 0
2 years ago
Help and explain please!
Igoryamba
84, first you multiply and divide then you add
6 0
2 years ago
Read 2 more answers
Please help me, I don't know how to do this...
Lunna [17]

Answer:

  A.  5

Step-by-step explanation:

The triangle will be a right triangle when the side lengths satisfy the Pythagorean theorem: the sum of the squares of the legs is equal to the square of the hypotenuse.

  (x +1)^2 +x^2 = (√61)^2

  x^2 +2x +1 +x^2 = 61 . . . eliminate parentheses

  2x^2 +2x = 60 . . . . . . .subtract 1, collect terms

  x^2 +x -30 = 0 . . . . . divide by 2, subtract 30

  (x +6)(x -5) = 0 . . . . factor the quadratic

  x = -6 or +5

The solution is x = 5.

_____

Side lengths cannot be negative. Solution values are values of x that make the factors zero. x+6=0 when x=-6, for example.

8 0
2 years ago
Please help!! See the attachment, please!​
topjm [15]

Answer:

946

Step-by-step explanation:

we know that

The formula to find the sum is equal to

S=(a1+an)n/2

where

a1 is the first term

an is the last term

n is the number of terms

In this problem we have

n=11

a1=(98-2(1))=96

an=(98-2(11))=76

substitute the values in the formula

S=(96+76)(11/2)=946

5 0
3 years ago
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