Answer:
x+6
Step-by-step explanation:
to find f(-x) plug in -x for all the values of x in the equation
since the absolute value of -x is x you get x+6
This would be 42 because 17+4•2=42
Answer:
P(B | T)=3/13
Step-by-step explanation:
The question is missing the Venn diagram that shows the value of each variable.
From the Venn diagram we can see there are 10 paintings that not T and not B. That means the total number of paintings that either T or B is
P(T∪B) = 60-10= 50 paintings.
There are x(x-2) + x paintings from 20th century
P(T)= x(x-2) + x = x^2 - x
There are 2x+8 +x British paintings.
P(B)= 2x+8 +x = 3x +8
There are 2 paintings that both T and B
P(T∩B)= x
Using union equation we can find the x
P(T∪B) = P(T) + P(B) - P(T∩B)
50= x^2 - x + 3x +8 - x
x^2 + x + 8 - 50 = 0
x^2 + x + -42 =0
(x-6) (x+7)=0
x1= 6 x2=-7
Since x can't be minus, then x=6.
The question asking how much conditional probability that a random T paintings is also British. The calculation will be:
P(B|T)= P(B∩T) / P(B) = x/ (3x +8)= 6/(6*3+8)= 6/26= 3/13
Answer:
Step-by-step explanation:
f(0) = -2
f(1) = 3*(f(1 - 1)) - 2*1
f(1) = 3(-2) - 2
f(1) = - 6 - 2
f(1) = - 8
f(2) = 3*(f(1)) - 2*2
f(2) = 3*(-8) - 4
f(2) = -24 - 4
f(2) = - 28
f(3) = 3*(f(2)) - 2*3
f(3) = 3*-28 - 6
f(3) = -84-6
f(3) = - 90
f(4) = 3*f(3) - 2 * 4
f(4) = 3*-90 - 8
f(4) = -270 - 8
f(4) = -278
(6,6). See how much was added to the first point, it’s 1,1 so add that to the other point also.