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1 year ago

Please help mee!! For which value of x does f(x) = 2?

Mathematics

2 answers:

kow [346]1 year ago

5 0

Answer:

um c I think, thats what g o o g l e says at least

Step-by-step explanation:

BARSIC [14]1 year ago

5 0

Answer:

The slope is zero

Step-by-step explanation:

0 | 2

1 | 2

3 | 2

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a chess player played 136 games total. If he won 56 of the games, what is the ratio of games he lost to games he won?

wolverine [178]

Answer:

80:56

Step-by-step explanation:

if you do 136-56, you get 80. therefore the number of games lost is 80. you already know he won 56, so the ratio is 80:56.

5 0

2 years ago

Guys help me please.<br> How to solve it?

pentagon [3]

I don’t have a calculator right now but a triangle always adds up to 180 degrees so yeah

7 0

2 years ago

Read 2 more answers

Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5

Marianna [84]

$\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}$

$\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)$

of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.

7 0

2 years ago

Does the graph represent a function?

AlekseyPX

Answer:

no it does not you can identify that by doing the vertical line test

Step-by-step explanation:

7 0

2 years ago

I need help with my math work

Gre4nikov [31]

Answer:

Go to tutoring, ask family, ask teacher, ask friend, or ask BRAINLY

Step-by-step explanation:

3 0

2 years ago