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3 years ago

❗❗CORRECT ANSWER+EXPLANATION=BRAINLIEST❗❗Simplify: (question in the pic)

Mathematics

2 answers:

Alexxandr [17]3 years ago

4 0

Step-by-step explanation:

x*2-9/x*2-3x

x*2-3*2/x*2-3x

(x-3)(x+3)/x(x-3)

x+3/x

Irina-Kira [14]3 years ago

3 0

Answer:

x +3

____

*line is a fraction line*

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Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

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$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

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2 years ago

F(x) = 5x^3+ 2x^2 - 90x - 36. <br><br> finding all zeros by factoring and explaining the steps

ella [17]

Answer:

f(x)=5x^3-2x^2-90x-36=0

=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0

x^2-18=0/5x-2=0

x^2=18=x=9√2

5x-2=0

x=2/5

zeros are 9√2,2/5

8 0

3 years ago

❗❗CORRECT ANSWER+EXPLANATION=BRAINLIEST❗❗Simplify: (question in the pic)​​

❗❗CORRECT ANSWER+EXPLANATION=BRAINLIEST❗❗Simplify: (question in the pic)