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Amiraneli [1.4K]
3 years ago
12

An engineer is designing a new dam for a river. The retaining wall of the dam will be angled such that the height above the grou

nd of the top at the wall is three times the horizontal distance between where it begins and where it ends at ground level. The outer angled wall will be 100 feet long this relationship is shown in the picture along with the rest of the question.
A: x+y=100
y=3x

B: x^2 + y^2 = 100^2
y= 3x

C: x+y=100
x=3y

D: x^2 + y^2 = 100^2
x=3y

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

B) x² + y² = 100²

   y = 3x

Step-by-step explanation:

The pythagorean theorem : a² + b² = c²

c² in this case is 100, and a and b are x and y

The . vertical distance is three times the horizontal, or y = 3x

The correct option is x² + y² = 100², where y = 3x

-Chetan K

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Answer:

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Step-by-step explanation:

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Bill has a ladder that is 8 1/2 feet tall. The ladder has 6 equal spaces between the rungs. How large is each space ?
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Step-by-step explanation:

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A kite is designed on a rectangular grid with squares that measure 1cm by 1 cm. A hexagonal piece within the kite will be reserv
Nata [24]

Answer:

The answer is the first answer

P = 8 + 4√13 cm

A = 36 cm²

Step-by-step explanation:

* Lets study the figure

- Its a kite with two diagonals

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- The longest one is 26 ⇒ axis of symmetry of the kite

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* To find the area reserved for the logo divide

 the hexagonal piece into two congruent trapezium

- The length of the two parallel bases are 4 cm and 8 cm and

  its height is 3 cm

- The length of non-parallel bases can calculated by Pythagoras rule

∵ The lengths of the two perpendicular sides are 2 cm and 3 cm

- 3 cm is the height of the trapezium

- 2 cm its the difference between the 2 parallel bases ÷ 2

  (8 - 4)/2 = 4/2 = 2 cm

∴ The length of the non-parallel base = √(2² + 3²) = √13

* Now we can find the area of the space reserved for the logo

- The area of the trapezium = (1/2)(b1 + b2) × h

∴ The area = (1/2)(4 + 8) × 3 = (1/2)(12)(3) = 18 cm²

∵ The space reserved for the logo are 2 trapezium

∴ The area reserved for the logo = 2 × 18 = 36 cm²

* The area of the reserved space for the logo = 36 cm²

* The perimeter of the reserved space for the logo is the

  perimeter of the hexagon

∵ The lengths of the sides of the hexagon are:

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∴ The perimeter = 2(4) + 4(√13) = 8 + 4√13 cm

* The perimeter of the reserved space for the logo = 8 + 4√13 cm

4 0
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Write the equation for g(x)
polet [3.4K]
I the answer is g(x)
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adelina 88 [10]

9514 1404 393

Answer:

  4) y = -3(x+2)^2 +4; y = -3x^2-12x-8; ABC=(-3, -12, -8)

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Step-by-step explanation:

Writing a quadratic equation through a set of points is most easily done using the regression function of a graphing calculator or spreadsheet.

4) see the first attachment

  y = -3(x+2)^2 +4 . . . vertex form

  y = -3x^2 -12x -8 . . . standard form (A, B, C) = (-3, -12, -8)

__

5) see the second attachment

  y = 0.5(x -1)^2 -2 . . . vertex form; vertex = (1, -2)

  y = 0.5x^2 -x -1.5 . . . standard form

__

6) see the third attachment

  y = -0.3(x +2)^2 -6 . . . vertex form; vertex = (-2, -6)

  y = -0.3x^2 -1.2x -7.2 . . . standard form

_____

Doing this without machine help requires you pick a form of the equation you want, fill in the x- and y-values for three of the given points, then solve the resulting equations for the unknown parameters. Usually, we use the form ...

  y = ax^2 +bx +c

which will result in three linear equations for a, b, c. Those can be solved by any of the usual methods.

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