Answer:
Step-by-step explanation:
Answer:
-35
Step-by-step explanation:
use your PEMDAS
5+(-4 -36)
5+(-40)
-35
Given hollow cubical box of side 0.30 m=3 dM
volume V=3^3=27 dm^3 = 27 L
Weight of box
= weight of (fresh) water (1 kg/L) displaced
= V/3 = 9 L of water = 9 kg
When water is filled so that the total weight of water equals the weight of volume of box, the top rim of the box will be at water level.
Remaining volume = 27-9=18L
height of 18L of water when water rushes in
= 18/(3^2) = 2 dm (=0.2m)
<h3>
Answer: 1</h3>
where x is nonzero
=======================================================
Explanation:
We'll use two rules here
- (a^b)^c = a^(b*c) ... multiply exponents
- a^b*a^c = a^(b+c) ... add exponents
------------------------------
The portion [ x^(a-b) ]^(a+b) would turn into x^[ (a-b)(a+b) ] after using the first rule shown above. That turns into x^(a^2 - b^2) after using the difference of squares rule.
Similarly, the second portion turns into x^(b^2-c^2) and the third part becomes x^(c^2-a^2)
-------------------------------
After applying rule 1 to each of the three pieces, we will have 3 bases of x with the exponents of (a^2-b^2), (b^2-c^2) and (c^2-a^2)
Add up those exponents (using rule 2 above) and we get
(a^2-b^2)+(b^2-c^2)+(c^2-a^2)
a^2-b^2+b^2-c^2+c^2-a^2
(a^2-a^2) + (-b^2+b^2) + (-c^2+c^2)
0a^2 + 0b^2 + 0c^2
0+0+0
0
All three exponents add to 0. As long as x is nonzero, then x^0 = 1
Answer:
Null hypothesis: H₀: ∪ = ≤ 393 pounds
Alternative hpothesis Hₐ: ∪ > 393 pounds
Step-by-step explanation:
The null hypothesis in this case is
Null hypothesis: H₀: ∪ = ≤ 393 pounds
Agriculture Scientists wish to test against this claim believing that the new fertilizer may increase the yield, thus the alternative hypothesis will be
Alternative hpothesis Hₐ: ∪ > 393 pounds.
