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4 31/50 as a mixed number
231/50 as an improper fraction
C
remove the parentheses
move the terms
collect like terms and calculate
divide both sides
and you get -13/8
6n + 5 < 20
Subtract both sides 5
6n + 5 - 5 < 20 - 5
6n < 15
Divide both sides by 6
6n ÷ 6 < 15 ÷ 6
n < 15/6
n < 3×5/3×2
n < 5/2
n < 2.5
n《 2
Thus the largest value of n is :
<h2>
<em>n</em><em> </em><em>=</em><em> </em><em>2</em><em> </em></h2>
