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jeka57 [31]
3 years ago
13

The following data show the weight, in ounces, of 10 different bags of candy:

Mathematics
2 answers:
Elden [556K]3 years ago
5 0

Answer:

On average, the weight of a bag of candy varies 2.6 ounces from the mean of 5 ounces.

Step-by-step explanation:

LuckyWell [14K]3 years ago
4 0
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean.  Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5

Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26

We now divide this by the number of data points:
26/10 = 2.6

This is a measure of how much each bag of candy varies from the mean.
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Answer:

The answer to your question is the letter A.

Step-by-step explanation:

Data

Center = (2, 3)

radius = 2

Process

1.- Find the equation of the line

              (x - h)² + (y - k)² = r²

-Substitution

              (x - 2)² + (y - 3)² = 2²  

-Simplification

              (x - 2)² + (y - 3)² = 4

-Evaluate the points in the equation

A. (4, 3)

              (4 - 2)² + (3 - 3)² = 4

                   2² + 0 = 4

                           4 = 4     This point lies in the circle

B (-1, 0)

              (-1 - 2)² + (0 - 3)² = 4

                        -3² + (-3)² = 4

                          9 + 9 = 4   This point is not part of the circle

C. (1, 3)

              (1 - 2)² + (3 - 3)² = 4

                 (-1)² + (0)² = 4

                            1 = 4          This point is not part of the circle

D. (3, 4)

              (3 - 2)² + (4 - 3)² = 4

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                            2 = 4          This point is not part of the circle

5 0
3 years ago
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What weather condition does the map indicate?
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3 years ago
Louisa ran at an average speed of five miles per hour along an entire circular park path. Calvin ran along the same path in the
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With Louisa's time find x:

x=5t_{L}\\ x=5(3)\\ x=15

7 0
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