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jeka57 [31]
3 years ago
13

The following data show the weight, in ounces, of 10 different bags of candy:

Mathematics
2 answers:
Elden [556K]3 years ago
5 0

Answer:

On average, the weight of a bag of candy varies 2.6 ounces from the mean of 5 ounces.

Step-by-step explanation:

LuckyWell [14K]3 years ago
4 0
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean.  Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5

Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26

We now divide this by the number of data points:
26/10 = 2.6

This is a measure of how much each bag of candy varies from the mean.
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using the point-slope formula, what is the equation of the line that passes through the points (1, 5) and (0, 0)? a. y = x b. y
Dmitry_Shevchenko [17]
First we find the slope m as follows:
m=\frac{y-y_{1}}{x-x_{1}}=\frac{5-0}{1-0}=5
So the equation is of the form:
y = 5x + b
When x = 1, y = 5. Therefore b = 0.
So the equation is:
y = 5x



4 0
3 years ago
What is the value of the function f(x) = 2x – 5 when x = 22? A17 B49 C105 D39
enyata [817]
<span>f(x) = 2x – 5

</span><span>f(22) = 2(22) – 5 = 44 -5 = 39

answer

</span><span>D39</span>
8 0
3 years ago
the small and the large intestine are part of the digestive system the small intestine longer than the large intestine and every
Bingel [31]
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7 0
3 years ago
Simplify (3x – 5) + (5x + 1).
Andrej [43]

Answer:

(-2x - 6)

Step-by-step explanation:

The given expression is ( 3x - 5 ) - ( 5x + 1 )

We have to simplify the given expression

First we will open the bracket having negative notation outside.

( 3x - 5 ) - 5x - 1

3x - 5 - 5x - 1

Now we will collect the similar terms together.

3x - 5x - 5 -1

-2x - 6

So the simplified form of the expression is (-2x - 6)

7 0
2 years ago
Read 2 more answers
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
3 years ago
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