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2 years ago

X-5/-2=x-1/-3 help pls

Mathematics

2 answers:

DerKrebs [107]2 years ago

7 0

Answer:

0=-13/6

Step-by-step explanation:

bulgar [2K]2 years ago

7 0

Answer:

x= -15/8

x= -1.875

x= -1 7/8

they are all correct

Step-by-step explanation

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Cynthia is planning a party. for entertainment, she has designed a game that involves spinning two spinners. if the sum of the n

vesna_86 [32]

The correct statement of the problem is attached

Spinner A: 4 parts, 3/4 is 1, 1/4 is 3.----------1 1 1 3
Spinner B: 3 parts, 1/3 is 5, 1/3 is 7, 1/3 is 9--------5 7 9

The combinations of the two spinners are
1 and 5
1 and 7
1 and 9
3 and 5
3 and 7
3 and 9

cases get you thrown in the pool
1 and 5
1 and 7
3 and 5

calculation of the probabilities
1 and 5--------3/4*1/3 = 1/4
1 and 7--------3/4*1/3 = 1/4
3 and 5--------1/4*1/3 = 1/12
1/4+1/4+1/12=7/12-----------58.33%

probabilities that the guests will be thrown in the pool--------58.33%

5 0

3 years ago

A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na

Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply the average speed formula, which is defined by:

$v=\frac{d}{t}$

where d is the total distance traveled and t is the total time needed.

$d=\frac{4.00}{1.75}=2.29$ km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0

3 years ago

(x2 − 8x + 5) − (−3x2 + 5x − 9)

julia-pushkina [17]

(X²-8X+5)-(-3X²+5X-9)
=X²-8X+5+3X²-5X+9
=4X²-13X+14
That's your answer lovely~

7 0

3 years ago

A pile of newspaper was 17 3/4 inches high. Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inc

Murljashka [212]

Answer: the height in inches, of the pile after 3 weeks is 34 11/12 inches

Step-by-step explanation:

Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inches. Converting 8 7/12 inches to improper fraction, it becomes 103/12 inches. The height is increasing in an arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 17 3/4= 71/4 inches

d = 103/12 inches

n = 3 weeks

the height in inches, of the pile after 3 weeks, T3. Therefore,

T3 = 71/4 + (3 - 1)103/12

T3 = 71/4 + 2 × 103/12 = 71/4 + 103/6

T3 = 419/12 inches = 34 11/12 inches

7 0

3 years ago

A dieter believes that the average number of calories in a homemade peanut better cookie is more than the average number of calo

zalisa [80]

The confidence interval formula is computed by:

Xbar ± Z s/ sqrt (n)

Where:

Xbar is the mean

Z is the z value

S is the standard deviation

N is the number of samples

So our given are:

90% confidence interval with a z value of 1.645

Sample size 40, 45

Mean 180, 179

Standard deviation 2, 4

So plugging that information in the data will give us a confidence interval:

For 1:

Xbar ± Z s/ sqrt (n)

= 180 ± 1.645 (2 / sqrt (40))

= 180 ± 1.645 (0.316227766)

= 180 ± 0.520194675

= 179.48, 180.52

For 2:

Xbar ± Z s/ sqrt (n)

= 179 ± 1.645 (4 / sqrt (45))

= 179 ± 1.645 (0.596284794)

therefore, the answer is letter b

8 0

3 years ago