The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.
Answer:don’t understand
Step-by-step explanation:
(6,-7)
This is because if the midpoint to one endpoint goes right 1 and up 5, then the other endpoint will be left 1 and down 5
Part a)
The shape of the pool is rectangular prism, so the volume of the pool will be:
Volume = Length x Width x Depth
Volume = 6 x 3 x 1 = 18 cubic meters
Density of water = 1 gram per cubic centimeter
Density of water = 1,000,000 gram per cubic meter
Density of water = 1000 kilogram per cubic meter
Mass, volume and density are related by the following equation:
Mass = Density x Volume
Using the values, we can write:
Mass of water in pool = 1000 x 18 =18,000 kilogram
Part b)
Mass of water added to pool = 6000 kilograms
Density of water = 1000 kilogram per cubic meter
Volume = Mass/Density
Volume of water in the pool = 6 cubic meter
Since Volume = Length x Width x Depth
6 = 6 x 3 x Depth
⇒ Depth = 1/3 meters
Can be rearranged as 4×2×a×b×c×4×9×a×b×7×c×3 negative and negative get cancelled off the seperate numerals from unknown values the we get 6048(abc) squared
