All categories

3 years ago

WhY DoEs MoMmUy JuMp UP AND DOWN IN THDOSE MUDDY MUDDY POODLES

SAT

1 answer:

Artyom0805 [142]3 years ago

7 0

Answer:

because shes a piggy.

Explanation:

You might be interested in

Which process involves a decrease in temperature?

Bond [772]

Boiling an egg will decrease the temperature during the process

4 0

3 years ago

John has always had a tendency to lie. He does not feel remorse for his wrongdoings. He fails to show sympathy and compassion to

nasty-shy [4]

John is a B.passionate criminal because he lies just for the heck of it. Hope i helped.

3 0

3 years ago

Read 2 more answers

Who are the characters in the poem "the mending wall"?

Paraphin [41]

Answer:

two characters: speaker and the neighbor

Explanation:

6 0

3 years ago

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago

Which technology do online stores usually use to present customized content?

eimsori [14]

Real-time analytics
Hope this helps..If so, please mark brainliest

3 0

3 years ago

Read 2 more answers