In Europe, the themes that are emphasized through the paintings of Christmas include the following:
- The birth of Jesus Christ.
- Joy and happiness among family members.
- Virgin Mary reclining and holding Jesus Christ as a priceless possession.
In Visual art, a theme can be defined as a broad and deeper meaning that is being conveyed by a piece of artwork (painting). Thus, it is primarily related to the meaning and main purpose of an artwork (painting) rather than the subject.
Christmas is an annual event that is celebrated by Christians in remembrance of the birth of their lord and personal savior, who is Jesus Christ. Also, Christmas is generally celebrated across the world on the 25th of December of every year.
In Europe, the themes that are emphasized through the paintings of Christmas include the following:
- The birth of Jesus Christ.
- Joy and happiness among family members.
- Virgin Mary reclining and holding Jesus Christ as a priceless possession.
Read more on Christmas here: brainly.com/question/24389251
The expression is a product expression
The denominator of the simplified fraction is 3n -2
<h3>How to determine the denominator?</h3>
The expression is given as;
Divide the first fraction by 2/2
Evaluate the above product
The above fraction is a simplified fraction of , and the denominator is 3n - 2
Hence, the denominator of the simplified fraction is 3n -2
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The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
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The answer is 7 because if you divide 35 by 5 you get 7
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