Which maternal condition is considered a contraindication for the application of internal monitoring devices?<span>Unruptured membranes In order to apply internal monitoring devices, the membranes must be ruptured.</span>
Answer:
1) Firstly, lets sort out the alleles for the dominant and recessive characteristics. The dominant brown allele will be written as B and the recessive red hair allele will be written as b.
2) Lets sort out the genotype of the parents. The parent having homozygous brown coloured hair will carry the alleles BB. The parent carrying the heterozygous brown coloured hair will carry the alleles Bb.
3) The punnet square from these parents will be drawn as follows:
B b
B BB Bb
B BB Bb
4) Now, lets predict the phenotype of the offsprings. The results from the punnet square show that all of the offsprings will have brown coloured hair.
5) The genotype for the children will have 50% chance to be homozygous brown (BB) and 50% chance to be heterozygous brown (Bb).
28.5 is quantitative data
<span>The interventions to improve the child's sleep is mainly based on the household behaviors such as eating meals together as a family, obtaining adequate sleep, limiting TV time, and removing the TV from the child’s bedroom, making the child to be so active in the morning time, engaging your child when they got bored, make them to feel tired by doing lot of physical activities, etc., By doing such activities from morning to evening, They feel so tired and make them to sleep after dinner.</span>
