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Mama L [17]
3 years ago
13

What time is it where you guys are at??

Mathematics
2 answers:
OLEGan [10]3 years ago
5 0

Answer:

dose meen nambars

Step-by-step explanation:

dont ansor kweschins nambars kweschins

frosja888 [35]3 years ago
3 0

5 in the morning unfortunately cuz I have massive insomnia

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How many three-digit numbers can be formed using elements from the set {1, 2, 3, 4, 5, 6} if no element may be used more than on
makkiz [27]

Answer:

60

Step-by-step explanation:

A 3-digit number can be odd only when the third digit in it would be odd.

So,

The 3rd digit becomes the most limiting which can be (1, 3, or 5).

Now,

Since we have 3 alternatives to pick the third digit, it can be done in three ways. For every of these 3 ways, 5 digits will be left to select the 1st. Thus, the number of ways to select 3rd and 1st digit = 3 * 5 = 15 ways

After picking the 1st and 3rd digits, we are left with 4 ways to pick the other 4 digits. Thus, the total number of ways to select all the digits would be;

3 * 5 * 4 = 60 ways

Hence, 60 is the correct answer.

5 0
3 years ago
Describe the process you used to write the equation of a line through two points.
xenn [34]
You can use point slope formula.  
y- y_{1}=m(x- x_{1})
By getting the slope (m) from ∆y/∆x
You can plug it into the equation and plug in either of the two points as x1 and y1.  This will result in the value for b.  Plug that into the final equation and you have your answer!
6 0
3 years ago
The average adult spends 7 to 8 hours sleeping. About 20% of the time you sleep is spent in rapid eye movement (REM) sleep which
maksim [4K]

Answer:

.20(7) ≤ x .20(8)

Step-by-step explanation:

let 'x' = amount of time in REM sleep

5 0
3 years ago
Evaluate the interval (Calculus 2)
Darya [45]

Answer:

2 \tan (6x)+2 \sec (6x)+\text{C}

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x

\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}

If the terms are multiplied by constants, take them outside the integral:

\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x

Multiply by the conjugate of 1 - sin(6x) :

\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x

\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x

\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:

\implies \sin^2 (6x) + \cos^2 (6x)=1

\implies \cos^2 (6x)=1- \sin^2 (6x)

\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x

Expand:

\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x

\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:

\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x

\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x

\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}

\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int  \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}

\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}

Simplify:

\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}

\implies 2 \tan (6x)+2 \sec (6x)+\text{C}

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0
2 years ago
Can you help please???????? ANYBODY this is important
olga_2 [115]
It’s D I hope I’m not late
7 0
3 years ago
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