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3 years ago

Figure ABCD is a trapezoid.

Mathematics

1 answer:

sertanlavr [38]3 years ago

3 0

(BC + AD) / 2 = 17

(2x + 1 + 3x + 8) / 2 = 17

5x + 9 = 34

5x = 25

x = 5

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The length of a rectangle is 2 feet longer than its width the perimeter is 16 feet. find the dimensions of the rectangle.

sergiy2304 [10]

So you would have to set up a equation to find the length and width. The equation would be w+(w+2)=16

that simplifies to 2w+2=16

2w=14

w=7

the width is 7

the length is 9

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Hello! answer: 9

Step-by-step explanation:

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What is the product of 306 and 15?

Mars2501 [29]

Product means to multiply.
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Please help me with 2b ASAP. <br> Really appreciate it!!

Bogdan [553]

$f(x)=\dfrac{x^2}{x^2+k^2}$

By definition of the derivative,

$f'(x)=\displaystyle\lim_{h\to0}\frac{\frac{(x+h)^2}{(x+h)^2+k^2}-\frac{x^2}{x^2+k^2}}h$

$f'(x)=\displaystyle\lim_{h\to0}\frac{(x+h)^2(x^2+k^2)-x^2((x+h)^2+k^2)}{h(x^2+k^2)((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{(x+h)^2-x^2}{h((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2x+h}{(x+h)^2+k^2}$

$f'(x)=\dfrac{2xk^2}{(x^2+k^2)^2}$

$\dfrac{k^2}{(x^2+k^2)^2}$ is positive for all values of $x$ and $k$ . As pointed out, $x\ge0$ , so $f'(x)\ge0$ for all $x\ge0$ . This means the proportion of occupied binding sites is an increasing function of the concentration of oxygen, meaning the presence of more oxygen is consistent with greater availability of binding sites. (The question says as much in the second sentence.)

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