This question is impossible to solve.
this is why:
if 4x-4=0
then x=1
so if 8x + 4 = 8
then x is false.
I get these question quite a lot in my GCSEs.
you have to prove why they are fake.
Try plugging in 4,6, and -7 into the x's
I have no problem answering but it wont let me open the pdf. I will gladly give you your points back just thought that you should know
Answer:
The correct option is;
Increasing one fifth unit/sec
Step-by-step explanation:
The equation that gives the curve of the particle of the particle is y = 5·x² - 1
The rate of decrease of the y value dy/dt = 2 units per second
We have;
dy/dx = dy/dt × dt/dx
dy/dx = 10·x
dy/dt = 2 units/sec
dt/dx = (dy/dx)/(dy/dt)
dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)
When x = 1
dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec
dx/dt = 1/5 unit/sec
Therefore, x is increasing one fifth unit/sec.
So, given a quadratic function, y = ax2<span> + bx + c, when "a" is positive, the </span>parabola<span> opens upward and the vertex is the </span>minimum<span> value. On the other hand, if "a" is negative, the graph opens </span>downward<span> and the vertex is the </span>maximum<span> value. To put it in complicated terms. Or when A is positive the graph is shaped like a U but if A is negative the graph is an upside down U
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