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chubhunter [2.5K]
2 years ago
13

I NEED HELP W THIS ASAP!!!!!

Mathematics
1 answer:
olga_2 [115]2 years ago
4 0

Answer:

18

Step-by-step explanation:

\frac{28}{14}  = 2 \\  \frac{36}{x}  = 2 \\ x =  \frac{36}{2}  \\  = 18

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the stove and the freezer weigh at least 260kg. the stove weighs 115 kg. How much would the freezer weigh?
Aleks [24]
About 145 I gonna guess I dont know if that's right
7 0
3 years ago
Read 2 more answers
Write each number without exponent 6.453 x 10^-3
Solnce55 [7]

Answer:

.006453

Step-by-step explanation:

6.453 x 10^-3

Move the decimal 3 places to the left since the exponent is negative

006.453

.006453

7 0
3 years ago
The price of a ring was decreased by 25% to £390. <br> What was the price before the decrease
Over [174]
You will pay $292.5 for a item with original price of $390 when discounted 25%. In this example, if you buy an item at $390 with 25% discount, you will pay 390 - 97.5 = 292.5 dollars
7 0
3 years ago
A bag contains seven tiles labeled B, C, D, E, F, G, and H. One tile will be randomly picked. What is the probability of picking
Licemer1 [7]

Answer:

\sf \dfrac{1}{7}

Step-by-step explanation:

Given labeled tiles: B, C, D, E, F, G, H

Total number of tiles = 7

Vowels = A, E, I, O and U

⇒ Total number of vowel tiles in bag = 1

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf Probability\:of\:picking\:a\:vowel= \dfrac{Number\:of\:vowel\:tiles}{Total\:number\:of\:tiles}=\dfrac{1}{7}

7 0
3 years ago
Determine whether the following are subspaces of R2×2 : (a) Thesetofall2×2diagonalmatrices (b) The set of all 2 × 2 triangular m
Mrrafil [7]

A vector space V is a subspace of a vector space W if

  • V is non-empty,
  • for any two vectors v_1,v_2\inV we have v_1+v_2\in V, and
  • for any scalar k and v\in V we have kv\in V.

It's easy to show the first condition is met by all the sets in parts (a-g).

(a) is a subspace of \Bbb R^{2\times2} because adding any 2x2 diagonal matrices together, or multiplying one by some scalar, gives another diagonal matrix.

(b) and (c) are also subspaces for the same reasons.

(d) is not a subspace because \Bbb R^{2\times2} because this set of matrices does not contain the zero matrix.

(e), however, is a subspace. Any linear combination of matrices in this set always yields a matrix with 0 in row 1, column 1 entry.

(f) is a subspace. A symmetric matrix is one of the form

\begin{bmatrix}a&b\\b&c\end{bmatrix}

Adding two symmetric matrices gives another symmetric matrix:

\begin{bmatrix}a_1&b_1\\b_1&c_1\end{bmatrix}+\begin{bmatrix}a_2&b_2\\b_2&c_2\end{bmatrix}=\begin{bmatrix}a_1+a_2&b_1+b_2\\b_1+b_2&c_1+c_2\end{bmatrix}

(g) is not a subspace. Consider the matrices

\begin{bmatrix}1&0\\0&0\end{bmatrix},\begin{bmatrix}0&0\\0&1\end{bmatrix}

Both matrices have determinant 0, but their sum is the identity matrix with determinant 1.

4 0
4 years ago
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