Y= kx (k being a constant)
10= k × 4 k=5/2
y= 5x/2 The answer is C.
Answer:
10 = 2y + 4
6 = 2y
y = 3
Step-by-step explanation:
18 = 10 + 2x
8 = 2x
x = 4
Answer:
You are given:
4Fe+3O_2 -> 2Fe_2O_3
4:Fe:4
6:O_2:6
You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.
For added benefit consider the following equation:
CH_4+O_2-> CO_2+2H_2O
ASK: Is this equation balanced? Quick answer: No
ASK: So how do we know and how do we then balance it?
DO: Count the number of each atom type you have on each side of the equation:
1:C:1
4:H:4
2:O:4
As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:
CH_4+color(red)(2)O_2-> CO_2+2H_2O
1:C:1
4:H:4
4:O:4
Everything is now balanced.
Step-by-step explanation:
Answer:
y= 20
Step-by-step explanation:
y=2*5x
Let x =2
y = 2*5 (2)
y = 10*2
y= 20
Well first off if you have a negative sign in front of the seven, DO NOT have a plus sign because it will be confusing. So y-7=13? , You add 7 to 13 and = 20, so y= 20
