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2 years ago

HELP ME OUT PLEASE!!!

Mathematics

1 answer:

ANTONII [103]2 years ago

7 0

Answer:

D) y= 4x - 1

Step-by-step explanation:

We are basically trying to see which of the equations provided are true on both sides of the equal sign when you plug in the x and y values.

Let's start!

Choice A:

plug in 0 for x and -1 for y

-1 = 4(0)

And you are left with...

-1 = 0

This equation is false! Therefore it does not match the function in the table

Choice B:

plug in the values again

-1 = 0 + 1

-1 = 1

False!

Choice C:

-1 = 0 + 5

-1 = 5

False!

Lastly...Choice D:

-1 = 4(0) -1

Multiply 4 and 0 which is 0, so you are left with...

-1 = -1

This equation is true!!

So your answer is D

Hope this helps :D

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A flower box in the shape of a right rectangular prism is made of thin metal, shown below. The box has length 90 centimeters (cm

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The volume of the box is
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3 years ago

Read 2 more answers

Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?

worty [1.4K]

Answer:

Step-by-step explanation:

$(x+y+z)(xy+xz+yz)=18$ Equation 1

$x^2(y+z)+y^2(x+z)+z^2(x+y)=6$ Equation 2

What is the value of $xyz$ where each variable represents a real number?

Let's expand equation 1:

$(x+y+z)(xy+xz+yz)=18$

$x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18$

Simplify each term if can:

$x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18$

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have $x^2$ and if I factored $x^2$ from first two terms I would have $x^2(y+z)$ which is the first term of left hand side of equation 2.

So let's see what happens if we gather the terms together that have the same variable squared together.

$x^2y+x^2z+y^2x+y^2z+z^2y+z^2x+xyz+xyz+xyz=18$

Factor the variable squared terms out of each binomial pairing:

$x^2(y+z)+y^2(x+z)+z^2(y+x)+xyz+xyz+xyz=18$

Replace the sum of those first three terms with what it equals which is 6 from the equation 2:

$6+xyz+xyz+xyz=18$

Combine like terms:

$6+3xyz=18$

Subtract 6 on both sides:

$3xyz=12$

Divide both sides by 3:

$xyz=4$

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2 years ago

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3 years ago

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nexus9112 [7]

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Step-by-step explanation:

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Now, the formula goes thus:

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