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3 years ago

A line with a slope of 3 passes through the point (2, 5). Write an equation for this line in point-slope form.

Mathematics

2 answers:

cestrela7 [59]3 years ago

8 0

Y-5=3(x-2) is point slope form. y-y1=m(x-x1) is the general equation for point slope.

Phantasy [73]3 years ago

3 0

Answer:

slope = 3

point (2, 5)

b = y - m*x

b = 5 -3*2

b = -1

Then we enter the slope and the value of b into this equation:

y = mx + b

y = 3x -1

Source: https://www.1728.org/distance.htm

Step-by-step explanation:

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Answer: z=83/c - 7 + t

Step-by-step explanation:

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3 years ago

A food company distributes its tomato soup in two cans of different sizes. For the larger can, the diameter has been increased b

Murrr4er [49]

Answer:

Step-by-step explanation:

buenas tardes .....

solucion

Volumen de un cilindro: es igual al área de la tapa por la altura del mismo

A = πD² * h / 4

Lata grande y lata pequeña

Para la lata grande, el diámetro y la altura han aumentado un 20%.

Lata pequeña:

d = 4 cm

h = 3 cm

A 1 = π * (4) ² * 3/4

A1 = 37,70 cm²

Lata grande:

d = 4 * 1,2 = 4,8 cm

h = 3 * 1,2 = 3,6 cm

A2 = π (4,8) ²3,6 / 4

A2 = 65,14 cm²

Si 37,7 representa el 100%

65,14 representación x

x = 170%

El incremento del volumen es de un 70%

6 0

3 years ago

At what position on the number line is the red dot located?

Lostsunrise [7]

Answer:

square root of 7

Step-by-step explanation:

2 times 2 is 4

3 times 3 is 9

7 is the only option between 4 and 9

(this was more the easy method lol but hope this helps)

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3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

4 years ago

How can you explain the answer 4 divided by 5

Sergio [31]

Answer:

4 divided by 5 is equal to 0.8. This decimal can also be written as a fraction. 0.8 = eight tenths or 8/10 (4/5 in its reduced form).

Step-by-step explanation:

3 0

3 years ago

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