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Oksana_A [137]
2 years ago
11

Is (7,-2) a solution to the equation x - 4y = 15? Please show work to help me understand.

Mathematics
1 answer:
grin007 [14]2 years ago
8 0

Answer:

yes

Step-by-step explanation:

x - 4y = 15

Substitute the point into the equation and see if the equation is true

7 -4(-2) = 15

7+8 = 15

15 =15

This is true so the point is a solution to the equation

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B and A if Im not wrong hope I didn’t get it wrong
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3 years ago
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Caleb and two friends are sharing a half quart of milk equally what fraction of a quart of milk does each other friend get
AveGali [126]
To find out what fraction of the half quart each friend will get, divide the 1/2 quart into 2 groups.

1/2 divided by 2 is the same as 1/2 x 1/2 or 1/4 quart.

Each friend will get 1/4 quart of milk.
5 0
3 years ago
Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
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A bug is moving back and forth on a straight path. The velocity of the bug is given by vt=t2-3t. Find the average acceleration o
g100num [7]

Answer:

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Step-by-step explanation:

Given the equation:

v(t) =t^2-3t

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V(1) = 1^2 - 3(1)

V(1) = 1 - 3

V(1) = - 2

At t = 4

V(4) = 4^2 - 3(4)

V(4) = 16 - 12

V(4) = 4

Average acceleration : (final - Initial Velocity) / change in time

Average acceleration = (4 - (-2)) ÷ (4 - 1)

Average acceleration = (4 + 2) / 3

Average acceleration = 6 /3

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Find the perimeter of this problem
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Answer: 119 4/7

Step-by-step explanation:

Add all the sides together.

4 0
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