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Andre45 [30]
3 years ago
7

Problem 3.2

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

Answer:

it is Circumference this is my answer

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What is the value of x?​
LiRa [457]

Answer:

98°

Step-by-step explanation:

x = 53° + 45° { exterior angle of a triangle is equal to the sum of two opposite interior angles }

x = 98°

5 0
2 years ago
What is the value of K?<br> k =<br> 8<br> o<br> 4<br> k<br> N<br> 1<br> M
Vsevolod [243]

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m

Step-by-step explanation:

it should be

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Joshua babysits for his sister after school. He is paid
Darina [25.2K]
The answer is 14.50. Hope that helped
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An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
Given the equation:
Alisiya [41]

Answer:

x = 1 and x = \frac{-4}{5}

Step-by-step explanation:

In this equation, a=5, b=-1, c=-4.

Plug these into the quadratic formula:

x = \frac{1+\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}   and x = \frac{1-\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}

Now, simplify the equations:

x = \frac{1+\sqrt{81} }{10} = \frac{1+9}{10} = \frac{10}{10} = 1

and

x = \frac{1-\sqrt{81} }{10} = \frac{1-9}{10} = \frac{-8}{10} = \frac{-4}{5}

5 0
3 years ago
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