All categories

3 years ago

What’s the total distance he travels

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

Answer:

Step-by-step explanation:

find the length of each leg, being 6 and 8. Then use the pythagorean theorem a^2+b^2=c^2

6^2+8^2=c^2

36+64=c^2

100=c^2

c=10

hope this helped... if it did, please let me know by marking me the brainliest:))

You might be interested in

How many three-person relay teams can be chosen from six students?

oksano4ka [1.4K]

2 because 6 divided by 3 is 2

hope i helped

6 0

3 years ago

Read 2 more answers

Please help me please

olga nikolaevna [1]

Answer:

BF = 30

Step-by-step explanation:

Since B and F are midpoints then BF is parallel to CE and half it's size

BF = 0.5 × CE = 0.5 × 60 = 30

3 0

3 years ago

Whats the density of an object with the length of 5.0 cm a height of 3.0 and width of 15.0 cm and a mass of 24 grams

Sphinxa [80]

Answer:

The density of the object is $0.1067$ grams per cubic centimeter. (Rounded off to 4th decimal)

Step-by-step explanation:

Density = [Mass/Volume]

Here we have been given the dimensions of the object.

Volume = Height * Width * Length

Volume = $3.0cm*15.0cm*5.0cm$

= $225cm^{3}$

Now we can substitute the Mass and the Volume to the density equation.

Density = [Mass/Volume]

= $\frac{24grams}{225cm^{3} }$

= $0.1067$ grams per cubic centimeter. (Rounded off to 4th decimal)

4 0

3 years ago

An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 1.6

nexus9112 [7]

Answer:

n=1705

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=1.6)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{1.6}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 2.58$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{2.58(1.6)}{0.1})^2 =1704.03$

And if we round up the answer we see that the value of n to ensure the margin of error required $\pm=0.1$ mm is n=1705.

6 0

3 years ago

John goes running every morning. He can run 3 miles in 1 hour. How many miles would he be able to run in 1 and ½ hours? A. 4.5 m

BARSIC [14]

Answer:

Step-by-step explanation:

well less than 3

7 0

3 years ago

Read 2 more answers