What is the solution of this system of equations?
1 answer:
Answer:
B. (-2,3)
Explanation:
First, we'll turn both lines to slope-intercept form:
x + 3y = 7
Subtract x on both sides to get 3y = -x + 7, then divide 3 on both sides to get y = -1/3x + 7/3.
3x + 2y = 0
Subtract 3x on both sides to get 2y = -3x, then divide 2 on both sides to get y = -3/2x.
Now you can graph (I did it for you above⤴⤴⤴).
Hope this helps you :)
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we are given
now, we can compare it with
we can find b
we get
now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8
b=1.6
b=1.4
b=1.2
now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
