Answer:
88
Step-by-step explanation:
If there are 111 balls of 4 colors, if 100 are taken, and each at least 1 of each color appears, there has to be at least 12 of each color (if you take 100 marbles of 3 colors, all 11 of 1 color could still be in the box, so there has to be at least 12 of each). If there are 12 marbles of 3 colors, there would be 111-(12×3)=111-36-75 marbles of the last color. To get at least 1 marble in 3 colors add 75+12+1=88. If there are 12 marbles of 2 colors, there would be a combined total of 87 marbles for the other 2 colors. 87+1=88. If there is 12 marbles of 1 color, there would be a combined total of 99 marbles for the other 3 colors. If there was a divide of 97+1+1, the 2 colors with only 1 marble could have still been left in the box when 100 balls were taken. So there has to be at least 12 of the colors. So we get 111-12-12-12=75, which is the maximum number of marbles that 1 color can have. 75+12+1=88, our previous answer.
Hope this helps! (P.S. Please give me branliest, it will help me achieve my next rank.)
53-45 off of the info that I have hope this helps
Answer:
x^2
Step-by-step explanation:
Answer:
basically u dont do it because it wount mean anything in da future.
Step-by-step explanation:
:)
Answer:
18$
Step-by-step explanation:
12.00 ÷ 2 = 6.00
6 + 12 = 18