Incomplete question as we have not told what to find.So I have assumed to find average CPI for each program.So complete question is here
Compilers can have a profound impact on the performance of an application. Assume that for a program, compiler A results in a dynamic instruction count of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a dynamic instruction count of 1.2E9 and an execution time of 1.5 s.
Find the average CPI for each program given that the processor has a clock cycle time of 1 ns.
Answer:
Step-by-step explanation:
As we know CPU time given as
For Compiler A
For Compiler B
Answer:
cos theta=-1/2
theta=cos-¹(-1/2)=120
tan theta=tan 120=-√3
sin theta=sin120=√3/2
cos(- theta)=cos theta=cos 120=-1/2
Answer:In 3 years, you will have $1,462.32
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
Answer:
1 oz of chips has 140 mg of sodium, and 1 cup of soda has 40 mg of sodium.
Step-by-step explanation:
This question is solved by a system of equations.
I am going to say that:
x is the amount of sodium in 1oz of chips.
y is the amount of sodium in 1 cup of soda.
Bryan ate 4 oz of chips and drank 1 cup of soda for a total of 600mg of sodium.
This means that 
, also 
Jadyn ate 1 oz of chips and drank 4 cups of soda for a total of 300mg of sodium.
This means that:
From the first equation, we have that . So
1 oz of chips has 140 mg of sodium, and 1 cup of soda has 40 mg of sodium.
