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Lynna [10]
2 years ago
13

Check

Mathematics
1 answer:
algol [13]2 years ago
6 0

Answer: Option A is the correct answer, y = x + 2

y - 3 = x-1

Step-by-step explanation:

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3 years ago
Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con
monitta

Let f(x)=e^{-1/x}. Then f'(x)=\frac1{x^2}e^{-1/x}>0 for all x\ge2, so f is strictly increasing. As x\to\infty, e^{-1/x}\to e^0=1, so f is bounded above by 1. This is to say,

e^{-1/x}

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3 years ago
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Ulleksa [173]

Answer:

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Step-by-step explanation:

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