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3 years ago

Find the slope of the line that passes through each pair of points (8,2) (8, -1)

Mathematics

1 answer:

mash [69]3 years ago

5 0

Answer:

Undefined

Step-by-step explanation:

Use the following formula to solve for slope:

$\frac{y_2-y_1}{x_2-x_1} =m$

$m=\frac{(-1)-2}{8-8}$

$m=\frac{-3}{0}$

The equation is not a function and therefore the slope is undefined because there are multiple y values for a single x value.

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In the morning, the number of ducks at the reservoir was 80. By noon, the reservoir had 135 ducks. What was the percent of chang

Mekhanik [1.2K]

Answer:

60 percent

Step-by-step explanation:

number of ducks in morning=80

ducks in after noon=135

for percentage

80/135=0.5925=0.60

0.60*100=60 percent

4 0

3 years ago

April shoots an arrow upward at a speed of 80 ft/sec from a platform of 25 ft. High. The pathway of the arrow can be represented

soldi70 [24.7K]

Answer:

125feet

Step-by-step explanation:

Given the equation that modeled the height expressed as h = -16t^2 + 80t + 25, where h is the height and t is the time in seconds.

The arrow reaches the maximum height at dh/dt = 0

dh/dt = -32t + 80

0= -32t+80

32t = 80

t = 80/32

t = 2.5secs

substitute t = 2.5 into the formula;

h = -16t^2 + 80t + 25

h = -16(2.5)^2 + 80(2.5) + 25

h = -16(6.25)+225

h = -100+225

h = 125

Hence the maximum height the arrow reaches is 125feet

4 0

3 years ago

Which of the following is the factored form of the given equation? 6x 2 + 2x - 8 = 0 2(3x + 4)(x - 1) = 0 (6x + 1)(x - 8) = 0 2(

Lelechka [254]

The correct answer for the question that is being presented above is this one: "2(x - 1)(3x + 4) = 0."

6x 2 + 2x - 8 = 0
(2x - 2) (3x + 4) = 0
2(x - 1)(3x + 4) = 0

The correct answer for the question that is being presented above is this one: "(x - 4)^2 = -19."

x2 - 8x + 3 =0
x2 - 8x + 16 = -3 - 16
(x - 4)(x - 4) = -19
(x - 4)^2 = -19

3 0

3 years ago

What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?

andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5) and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)

To Find:

M(x₄ ,y₄) = ? and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

$Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})$

As M is the mid point of PR and N is the mid point of RQ so we will have

$Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})$

$Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})$

Substituting the given value in above equation we get

$Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})$

∴ $Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})$

∴ $Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)$

Similarly,

$Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})$

∴ $Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})$

∴ $Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)$

∴ M(x₄ ,y₄) = (-3.5 , 0.5) and

N (x₅ ,y₅) = ( -1 , -0.5 )

3 0

3 years ago

What is the volume of a cylinder with base radius 3 and height 8? Either enter an exact answer in terms of \piπpi or use 3.14, f

sergiy2304 [10]

First find the area of the base, and multiply that by the height. That's the answer.

Area of the base: pi * 3*3 = 3.14*9 = 28.26
Volume of the cylinder: 28.26*8 = 226.08 cubic units

4 0

3 years ago

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