Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
yes Cecilia make her first mistake in step 2
Answer:
x=18
Step-by-step explanation:
ok, so you mulityply base and hieght then divide by 2
your base is 6 and your height is 6
6x6=36
36/2=18
your welcome
Answer:
take a more clear photo cant see well...
Step-by-step explanation:
but like if you re-take it ill help you....:)
