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Lunna [17]
3 years ago
8

Consider the following function.f(x) = e3x2, a = 0, n = 3, 0 ? x ? 0.2(a) Approximate f by a Taylor polynomial with degree n at

the number a.T3(x) =(b) Use Taylor's Inequality to estimate the accuracy of the approximation f(x) ? Tn(x) when x lies in the given interval. (Round your answer to five decimal places.)|R3(x)| ?
Mathematics
2 answers:
Maslowich3 years ago
7 0

Answer:

Given equation is given below

f(x) = e3x2, a = 0, n = 3, 0 ? x ? 0.2

Using Taylor's inequality

Approximate value of the function=2.4675

bekas [8.4K]3 years ago
5 0

Answer:

oof i havnt done that math in ages o-o

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2 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

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Step-by-step explanation:

Assuming the following data:

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117; 80

126; 77

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157; 90

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The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

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Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
2 years ago
2√3 ∙ 3√2<br> Multiple choice<br> 5√5<br> 5√6<br> 6√6<br> Not possible<br> None of the above
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2√3 ∙ 3√2= 6√6
alternate form- 14.69
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