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3 years ago

What is the fractional equivalent of the repeating decimal 04?

Mathematics

2 answers:

Nutka1998 [239]3 years ago

6 0

Answer:

Step-by-step explanation:

Novay_Z [31]3 years ago

5 0

Answer:

i think c

Step-by-step explanation:

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What should the first step be when solving for x?<br>-5x+6(-2x-13)=7

Juli2301 [7.4K]

Answer:

multiply the things in the () with6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the values of p and q such that 4x^2+12x=4(x+p)^2-q

-Dominant- [34]

Answer:

p = 1.5 and q = 9

Step-by-step explanation:

Expand the right side then compare the coefficients of like terms on both sides, that is

4(x + p)² - q ← expand (x + p)² using FOIL

= 4(x² + 2px + p²) - q ← distribute parenthesis

= 4x² + 8px + 4p² - q

Comparing coefficients of like terms on both sides

8p = 12 ( coefficients of x- terms ) ← divide both sides by 8

p = 1.5

4p² - q = 0 ( constant terms ), that is

4(1.5)² - q = 0

9 - q = 0 ( subtract 9 from both sides )

- q = - 9 ( multiply both sides by - 1 )

q = 9

7 0

3 years ago

If g(x) =4x+2 and f(x) =3x-10 <br><br> find g(f(3))

Leya [2.2K]

Answer:

$g(f(3))=-2$

Step-by-step explanation:

So we have the two functions:

$g(x)=4x+2\text{ and } f(x)=3x-10$

And we want to find g(f(3)).

So, let's find f(3) first:

$f(3)=3(3)-10$

Multiply:

$f(3)=9-10$

Subtract:

$f(3)=-1$

Therefore, we can substitute -1 for f(3):

$g(f(3))=g(-1)$

Now, find g(-1):

$g(-1)=4(-1)+2$

Multiply:

$g(-1)=-4+2$

Add:

$g(-1)=-2$

And we're done!

So:

$g(f(3))=-2$

6 0

4 years ago

Which pair of adjacent angles is complementary?

Artist 52 [7]

<h3>part d is pair of adjacent angle is supplementary </h3>

because the angle are complementary and common vertex so it is adjacent Two complementary angles with a common vertex and arm are called adjacent complementary angles

hope it's helpful thanks

8 0

2 years ago

Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)

Leviafan [203]

Answer:

$\huge\boxed{x=1\ \vee\ x=2}$

Step-by-step explanation:

$3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}$

$\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}$

4 0

3 years ago