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3 years ago

Find the exact value of sin(o) a. 0.0161 b. 0.7975 c. 12/13 d. 12/5

Mathematics

2 answers:

podryga [215]3 years ago

7 0

<u>Answer:</u>

The correct answer option is C. 12/13.

<u>Step-by-step explanation:</u>

We are given a right angled triangle with two known sides and we are to find the measure of the angle O.

For finding the measure of O, we will use sine for which we need to find the value of the value of the hypotenuse (MO).

$MO = \sqrt {(5)^2 + (12)^5} = \sqrt{169} = 13$

Now that we know the length of the hypotenuse, we can find sin (O).

$sin O = \frac{12}{13}$

Therefore, the correct answer option is C. 12/13.

Finger [1]3 years ago

4 0

Answer:

Step-by-step explanation:

We require to find the length of the hypotenuse (h)

Using Pythagoras' identity in the right triangle

h² = 5² + 12² = 25 + 144 = 169 ( take the square root of both sides )

h = $\sqrt{169}$ = 13

sinO = $\frac{opposite}{hypotenuse}$ = $\frac{MN}{MO}$ = $\frac{12}{13}$

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3 years ago

Calculate the length of AB. Round to the nearest tenth.

marissa [1.9K]

Answer:

AB = 10.06 cm

Step-by-step explanation:

Consider the given figure,

We have to find the length of side AB.

Lets rename the figure first, ABCD forms a rectangle. So , CB = DA = 12 cm

Also, EA = ED +DA ⇒ 15 = ED + 12 ⇒ ED = 15 - 12 ⇒ ED = 3 cm

Pythagoras theorem states that in a right triangle the sum of square of base and perpendicular is equal to square of hypotenuse.

Using, Pythagoras Theorem on Δ EDC,

$(EC)^2=(ED)^2+(DC)^2$

ED = 3 cm , EC = 10.5, Substitute, we get,

$\Rightarrow (10.5)^2=(3)^2+(DC)^2$

Solve for DC, we get,

$\Rightarrow 110.25=9+(DC)^2$

$\Rightarrow 110.25-9=(DC)^2$

$\Rightarrow (DC)^2=101.25$

$\Rightarrow DC=\sqrt{101.25}$

$\Rightarrow DC=10.06$

Since, ABCD is a rectangle. Thus, DC = AB

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