We can find area by calculating area of squre with side 27in minus area of square with side12in
Answer:
The independent quantity in the situation is the length of the diameter.
Step-by-step explanation:
Consider a relationship between two variables.
Of the two variables one variable is dependent upon the other.
Dependent variables are those variables that are under study, i.e. they are being observed for any changes when the other variable values are changed.
Independent variables are the variables that are being altered to see a proportionate change in the dependent variable.
In this case, it is provided that Grissom knows there is a relationship between the volume of the sphere and the length of its diameter.
With every sphere that Grissom draws, the volume of the sphere changes according to its diameter length.
That is the volume of the sphere depends upon the length of its diameter.
Thus, the independent quantity in the situation is the length of the diameter.
Answer:
F has 10 marbles and I has 5 marbles.
Step-by-step explanation:
First, I subtracted 10 from 15 since F has 10 more marbles than I. When I subtracted I got 5.
Hope this helps!!!!
Answer:
1
Step-by-step explanation:
First, convert all the secants and cosecants to cosine and sine, respectively. Recall that
and
.
Thus:


Let's do the first part first: (Recall how to divide fractions)

For the second term:

So, all together: (same denominator; combine terms)

Note the numerator; it can be derived from the Pythagorean Identity:

Thus, we can substitute the numerator:

Everything simplifies to 1.