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butalik [34]
3 years ago
15

Which statement is NOT true?

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0

Answer:

the answer is d.

Step-by-step explanation:

every parallelogram in NOT a rectangle.

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12. What is the value of x ?
Firlakuza [10]

Answer:

If that dot in the middle is the middle of the circle, then that should mean the center is 5 away from both of those lines. Therefore, I believe x would 9/2 or 4.5

4 0
2 years ago
25 as a percent compared to 30
BabaBlast [244]
7.5 i think not 100% sure tho
6 0
3 years ago
Read 2 more answers
Compute 33(0.5) - 6(0.5) - 7/2.
lora16 [44]
Hi there! The answer is 10.

33(0.5) - 6(0.5) -  \frac{7}{2}
We can use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Since we cannot work inside the parenthesis in this question and since we don't have exponents, we can move on to multiplying.
16.5 - 3 -  \frac{7}{2}

Our next step would be subtracting. To make the process of subtracting some easier, I'll first change the fraction into a decimal.
16.5 - 3 - 3.5

Finally subtract.
13.5 - 3.5 = 10

The answer is 10.
~ Hope this helps you!
5 0
3 years ago
Read 2 more answers
Justify each step. <br> x/3-7=11 <br> x/3=18<br> x=6
Nina [5.8K]
This is the steps for equation solving for the value of x,
x/3-7 = 11
now 7 goes to the other side of equation by changing the sign from - to +,
x/3 = 11 + 7
x/3 = 18
now when we multiply both sides of equation with 3 or 3 goes to the other side of equation and multiply with 18 leaving x alone here for finding the value of x,
and we get, x = 54
at the end of equation we get x = 54, if the equation was in the form 3x - 7 = 11, then we will get x = 6
8 0
3 years ago
Prove that if one solution for a quadratic equation of the form x 2 + bx + c = 0 is rational (where b and c are rational), then
erica [24]
x^2+bx+c = (x-r)(x-s)\\&#10;x^2+bx+c = x^2-(r+s)x+rs\\\\&#10;b = -(r+s)\\ c = rs

Say r is rational. Suppose for a second, that s is not. Then, r+s is irrational. But this contradicts the fact that b is rational.

So, if one root is rational, then the other root is also rational
7 0
3 years ago
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