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Novay_Z [31]
3 years ago
12

Please help me ASAP I don’t understand sigh

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

x = -2, y = -6

Step-by-step explanation:

(8x - 3y) + (-8x - 5y) = 2 + 46

-8y = 48

y = -6

8x - 3y = 2

8x - 3(6) = 2

8x + 18 = 2

8x = -16

x = -2

Evgesh-ka [11]3 years ago
8 0

Answer:

\boxed { \sf (-2, -6) }}

Step-by-step explanation:

We are asked to find the solution of the system of equations.

8x-3y=2\\-8x-5y=46

When we solve systems of equations, we have to do 2 steps. The first step eliminates one variable so we can solve for the other. The next step helps us find the variable we canceled.

The first equation has the term 8x and the second equation has the term -8x. If these are added, they cancel, so we are left with the variable y. Add the equations together.

(8x-3y=2) \\+ (-8x-5y=46)

8x and -8x cancel, then add.

(-3y=2)\\+ (-5y=46)

___________

-8y= 48

We are solving for y, so we must isolate the variable. It is being multiplied by -8. The inverse operation of multiplication is division. Divide both sides by -8.

-8y/-8=48/-8 \\y= 48/-8 \\y=-6

Now we know what y is equal to, so we can plug it back into one of the original equations and solve for x.

I chose the first equation.

8x-3y=2

8x-3(-6)=2

8x+18=2

Subtract 18 from both sides to isolate 8x.

8x+18-18=2-18\\8x=2-18\\8x=-16

Divide both sides by 8.

8x/8=-16/8 \\x=-16/8 \\x= -2

Coordinate points are written as (x,y) so our solution is <u>(-2, -6)</u>

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Show work and Factor 4x^2+xy-18y^2
grigory [225]

Answer:

4x^2+xy-18y^2=(4x+9y)\,(x-2y)

Step-by-step explanation:

Let's examine the following general product of two binomials with variables x and y in different terms:

(ax+by)\,(cx+dy)= ac\,x^2+adxy+bcxy+bdy^2

so we want the following to happen:

a\,c = 4\\ad+bc=1\\bd--18

Notice as well that ad+bc =1 means that those two products must differ in just one unit so, one of them has to be negative, or three of them negative. Given that the product bd=-18, then we can consider the case in which one of this  (b or d) is the negative factor. So let's then assume that a\,\,and \,\,c are positive.

We can then try combinations for  a\,\,and \,\,c  such as:

a = 4;\,\,c=1\\a=2;\,\,c=2\\a=1;\,\,c=4

Just by selecting the first one (a=4;\,\,c=1)

we get that 4d_b=1\\b=-4d-1

and since

bd=-18\\(-4d-1)\,d=-18\\-4d^2-d=-18\\4d^2+d-18=0

This quadratic equation give as one of its solutions the integer: d = -2, and consequently,

d=-18/(-2)\\d=9

Now we have a good combination of parameters to render the factoring form of the original trinomial:

a=4; \,\,b=9;\,\,c=1;\,\,d=-2

which makes our factorization:

(4x+9y)\,(x-2y)=4x^2+xy-18y^2

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