<span>D. Page Layout i hope this helps </span>
Answer:
Option(d) is the correct answer to the given question .
Explanation:
There are various type of algorithm is used for the purpose of the key scheduling such as AES .in the AES algorithm we used same key for encryption and decryption of text .The main objective of the AES algorithm it is used by Various round of the similar plain text encryption to reinforce the cipher text.
- The Option (a) is wrong because In the key scheduling the creating keys are not being used one after just another in the various communication cycles.
- The Option (b) is wrong because In the key scheduling we do not used the the random key for the encryption process .
- The Option (c) is wrong because we will never arbitrarily subdivided into groups of public and private key.
It depends on a language you code. I think this could be either C++ or Java. I know answer for both of them.
For C++: <span>address.find("Avenue")
For Java: </span><span>address.indexOf("Avenue")</span>
Answer:
Here is the Python program:
small_container = int(input("Enter the number of small containers you recycled?"))
large_container = int(input("Enter the number of large containers you recycled?"))
refund = (small_container * 0.10) + (large_container * 0.25)
print("The total refund for returning the containers is $" + "{0:.2f}".format(float(refund)))
Explanation:
The program first prompts the user to enter the number of small containers. The input value is stored in an integer type variable small_container. The input is basically an integer value.
The program then prompts the user to enter the number of large containers. The input value is stored in an integer type variable large_container. The input is basically an integer value.
refund = (small_container * 0.10) + (large_container * 0.25) This statement computers the refund that will be recieved for returning the small and larger containers. The small containers holding one litre or less have a $0.10 deposit so the number of small containers is multiplied by 0.10. The large containers holding more than one litre have a $0.25 deposit so the number of large containers is multiplied by 0.25. Now both of these calculated deposits of containers of each side are added to return the refund that will be received for returning these containers. This whole computation is stored in refund variable.
print("The total refund for returning the containers is $" + "{0:.2f}".format(float(refund))) This print statement displays the refund in the format given in the question. The output includes a $ sign and displays exactly two decimal places by using {0:.2f} where .2f means 2 decimal places after the decimal point. Then the output is represented in floating point number using. format(float) is used to specify the output type as float to display a floating point refund value up to 2 decimal places.