Question

Write a function safeOpen() that takes one parameter, filename — a string giving the pathname of the file to be opened for reading. When safeOpen() is used to open a file, a reference to the opened file object should be returned if no exception is raised, just like for the open() function. If an exception is raised while trying to open the file, safeOpen() should return the value None

Answer 1

My bad my friend was like that I don’t got it to go home I don’t want him texting him or whatever I don’t gotta is like I gotta do it