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Mice21 [21]
3 years ago
11

What is the property of this math problem please help

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

distributive property

Step-by-step explanation:

Because distributive property formula is a(b+c) = ab + ac

meaning that w(6+5) = 6w + 5w

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5 0
3 years ago
Use quadrilateral ABCD to find the value of x. The figure is not drawn to scale. Use the following dimensions: m⦨ABC = 4x◦, m⦨BC
OLEGan [10]

Answer/Step-by-step explanation:

Question 1:

Interior angles of quadrilateral ABCD are given as: m<ABC = 4x, m<BCD = 3x, m<CDA = 2x, m<DAB = 3x.

Since sum of the interior angles = (n - 2)180, therefore:

4x + 3x + 2x + 3x = (n - 2)180

n = 4, i.e. number of sides/interior angles.

Equation for finding x would be:

4x + 3x + 2x + 3x = (4 - 2)180

12x = (2)180

12x = 360

x = \frac{360}{12} (dividing each side by 12)

x = 30

Find the measures of the 4 interior angles by substituting the value of x = 30:

m<ABC = 4x

m<ABC = 4*30 = 120°

m<BCD = 3x

m<BCD = 3*30 = 90°

m<CDA = 2x

m<CDA = 2*30 = 60°

m<DAB = 3x

m<DAB = 3*30 = 90°

Question 2:

<CDA and <ADE are supplementary (angles on a straight line).

The sum of m<CDA and m<ADE equal 180°. To find m<ADE, subtract m<CDA from 180°.

m<ADE = 180° - m<CDA

m<ADE = 180° - 60° = 120°

6 0
3 years ago
Find the distance between A (-3,<br> - 4) and B (5. – 10).
Kamila [148]

Answer:

16.13

Step-by-step explanation:

Sorry!! if I am wrong....

7 0
3 years ago
Find the number which log reading is 6797​
Vitek1552 [10]

Answer:

The number is log 47base9

7 0
3 years ago
Please help with these
Nookie1986 [14]

The values would be

sin2x = -3/5

cos2x = -4/5

tan2x = 3/4

What are double angles in trigonometry?

The double angle formulas are used to find the values of double angles of trigonometric functions using their single angle values. For example, the value of cos 30° can be used to find the value of cos 60°. Also, the double-angle formulas can be used to derive the triple-angle formulas.

Given: tanx = -3

Now as we know,

                  sin2x=\frac{2tanx}{1+tan^2x}\\\\sin2x=\frac{2(-3)}{1+(-3)^2}\\\\sin2x=\frac{-6}{10}\\\\sin2x=\frac{-3}{5}

Now

               cos2x=\frac{1-tan^2x}{1+tan^2x}\\\\cos2x=\frac{1-(-3)^2}{1+(-3)^2}\\\\cos2x=\frac{1-9}{1+9}\\\\cos2x=\frac{-8}{10}\\\\cos2x=\frac{-4}{5}

And similarly, we can find the value of tan2x, as

                  tan2x = sin2x/cos2x

                             = (-3/5)/(-4/5)

                             = 3/4

Hence,

The values would be

sin2x = -3/5

cos2x = -4/5

tan2x = 3/4

To learn more about double angles in trigonometry, visit:

brainly.com/question/6277459

#SPJ1

6 0
1 year ago
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