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Mice21 [21]
2 years ago
11

What is the property of this math problem please help

Mathematics
1 answer:
lbvjy [14]2 years ago
8 0

Answer:

distributive property

Step-by-step explanation:

Because distributive property formula is a(b+c) = ab + ac

meaning that w(6+5) = 6w + 5w

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Use the simple interest formula to find the ending balance.
9966 [12]

Answer: 13,000

Step-by-step explanation:

I = prt

I = (.65)($4000)(5)

I = 2600(5)

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With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en
GuDViN [60]

Answer:

P = 0.1447

Step-by-step explanation:

Given

n = 7000 -- total

d = 180 --- defective

r = 6 --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}

Pr = 0.8553

Using the complement rule, the probability that the batch will be rejected is:

P = 1 - 0.8553

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8 0
2 years ago
Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
ser-zykov [4K]

Answer:

Step-by-step explanation:

Part 1:

Let 

     Q₁ = Amount of the drug in the body after the first dose.

     Q₂ =  250 mg

As we know that after 12 hours about 4% of the drug is still present in the body.

For Q₂,

we get:

            Q₂ = 4% of Q₁ + 250

                  = (0.04 × 250) + 250

                  = 10 + 250

                  = 260 mg

Therefore, after the second dose, 260 mg of the drug is present in the body.

Now, for Q₃ :

We get;

          Q₃ = 4% of Q2 + 250

               = 0.04 × 260 + 250

               = 10.4 + 250

               = 260.4

For Q₄,

We get;

          Q₄ = 4% of Q₃ + 250 

                = 0.04 × 260.4 + 250

                = 10.416 + 250 

                = 260.416

Part 2:

To find out how large that amount is, we have to find Q₄₀.

Using the similar pattern

for Q₄₀,

We get;

           Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹

Taking 250 as common;

           Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)

                 = 2501 − 0.04401 − 0.04

           Q₄₀ = 260.4167

Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.

Part 3:

From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.

3 0
3 years ago
Ninth grade math help me PLEASEEEE PLEASE
dusya [7]

Answer:

I believe the answer is D.

Step-by-step explanation:

3 0
2 years ago
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