Translate the sentence into an equation.

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

The probability that a passenger does not show up is 0.10:

This means that the probability of showing up is 1-0.1 = 0.9. So $p = 0.9$

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets

This means that $n = 125$

Using the approximation:

$\mu = E(X) = np = 125*0.9 = 112.5$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.9*0.1} = 3.354$

(a) What is the probability that every passenger who shows up can take the flight

This is $P(X \leq 120)$ , so this is the pvalue of Z when X = 120.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{120 - 112.5}{3.354}$

$Z = 2.24$

$Z = 2.24$ has a pvalue of 0.9875

98.75% probability that every passenger who shows up can take the flight

7 0

3 years ago

Please help me it’s almost due

Serhud [2]

I believe the answer is C

7 0

3 years ago

Krispy Kritters Cereal used to come in a

shtirl [24]

Answer:

1335cm³

Step-by-step explanation:

The question above says that,Krispy kritters cereal used to come in a box with a volume of 2,850 cm3. However, the krispy kritters co. Designed a new larger box 22.5 cm wide, 6.2 cm deep, and 30 cm high and we are now asked to find "How many more cubic centimeters will the new box hold than the old box?

Now we are all aware that the volume of a cube or cuboid(since its a box ) is length multipled by width multiplied by the height.

And we were given the new dimensions which are;

12.5cm wide

6.2cm deep and

30cm high

Apply this given figures in the formula above and we have:

V = 12.5 × 6.2 × 30

= 4185cm³( this is the volume of the box)

Therefore,the difference in volume between the new box and the old box is

4185 - 2850 = 1335cm³

5 0

3 years ago