For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
The solutions to q² - 125 = 0 are q = ±√125.
q = -5√5
q = 5√5
Answer:
37°
Step-by-step explanation:
Sum of angles in a triangle = 180°
So 96 + 47 = 143
180 - 143 = 37
4/10 multiplied to 2/3 is 4/15.
We have the following general rule for exponents:
then, in this case we have the following:
therefore, the answer is 3
