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velikii [3]
3 years ago
9

Let A= ????

Mathematics
1 answer:
hjlf3 years ago
7 0

Answer:

X = \begin{bmatrix}5 &-1 \\ -5 &4 \\2& -9\end{bmatrix}

Step-by-step explanation:

given,

A + X = Q

X = A - Q

A = \begin{bmatrix}3 &2 \\ -1 &5 \\3& -4\end{bmatrix}

Q =  \begin{bmatrix}-2 &3\\ 4 &1 \\ 1&-5\end{bmatrix}

now

X =  \begin{bmatrix}3 &2 \\ -1 &5 \\3& -4\end{bmatrix}-\begin{bmatrix}-2 &3\\ 4 &1 \\ 1&-5\end{bmatrix}

X = \begin{bmatrix}3-(-2) &2-3 \\ -1-4 &5-1 \\3-1& -4-5\end{bmatrix}

X = \begin{bmatrix}5 &-1 \\ -5 &4 \\2& -9\end{bmatrix}

hence, the required matrix is given above

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2 (3x+4y -z = -6)  => 6x + 8y -2z = -12
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                                  ------------------------
                                     11x + 16y = -10  -> this the fourth equation

use the first and third equation:
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-------------------------
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use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
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add 6th and 7th equation such as:
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---------------------------
             - 23y = 46
               <span>   y = -2

solving for x, we have:
</span>2x + 5y = -6 
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solving for y value, we have:
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z =4

The answers are the following:
x = 2
y = -2
z = 4
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