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velikii [3]
3 years ago
9

Let A= ????

Mathematics
1 answer:
hjlf3 years ago
7 0

Answer:

X = \begin{bmatrix}5 &-1 \\ -5 &4 \\2& -9\end{bmatrix}

Step-by-step explanation:

given,

A + X = Q

X = A - Q

A = \begin{bmatrix}3 &2 \\ -1 &5 \\3& -4\end{bmatrix}

Q =  \begin{bmatrix}-2 &3\\ 4 &1 \\ 1&-5\end{bmatrix}

now

X =  \begin{bmatrix}3 &2 \\ -1 &5 \\3& -4\end{bmatrix}-\begin{bmatrix}-2 &3\\ 4 &1 \\ 1&-5\end{bmatrix}

X = \begin{bmatrix}3-(-2) &2-3 \\ -1-4 &5-1 \\3-1& -4-5\end{bmatrix}

X = \begin{bmatrix}5 &-1 \\ -5 &4 \\2& -9\end{bmatrix}

hence, the required matrix is given above

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The nth term of a sequence is given by 3n² + 11 Calculate the difference between the 6th term and the 9th term of the sequence.​
katovenus [111]

The difference between the 6th term and the 9th term of the sequence is 135

<h3>How to determine the difference</h3>

Given that the nth term is;

3n² + 11

For the 6th term, the value of n is 6

Let's solve for the 6th term

= 3( 6)^2 + 11

= 3 × 36 + 11

= 108 + 11

= 119

For the 9th term, n = 9

= 3 (9)^2 + 11

= 3( 81) + 11

= 243 + 11

= 254

The difference between the 6th and 9th term

= 254 - 119

= 135

Thus, the difference between the 6th term and the 9th term of the sequence is 135

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2 years ago
A rectangular photo frame covers an area of 20 square inches on a wall. The width of the frame is 1 inch less than its length. F
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3 years ago
Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th
mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

g(x) = 3x^{2} - 42a + 135

So

a = 3, b = -42, c = 135

\bigtriangleup = (-42)^{2} - 4*3*135 = 144

x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9

x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

8 0
3 years ago
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