Not 100% sure but it might be B
The difference between the 6th term and the 9th term of the sequence is 135
<h3>How to determine the difference</h3>
Given that the nth term is;
3n² + 11
For the 6th term, the value of n is 6
Let's solve for the 6th term
= 3( 6)^2 + 11
= 3 × 36 + 11
= 108 + 11
= 119
For the 9th term, n = 9
= 3 (9)^2 + 11
= 3( 81) + 11
= 243 + 11
= 254
The difference between the 6th and 9th term
= 254 - 119
= 135
Thus, the difference between the 6th term and the 9th term of the sequence is 135
Learn more about algebraic expressions here:
brainly.com/question/4344214
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You need to find two factors of 20 that are consecutive: 4,5.
Answer: 5inx4in
Answer:
please mark as brilliant thanks
Answer:
g(x) = 3(x-9)(x-5)
Zeros: x = 9 and x = 5.
Step-by-step explanation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:

So




So
g(x) = 3(x-9)(x-5)
Zeros: x = 9 and x = 5.