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<span>Assuming that the language is C++ and that the following variables exist:
bonusscores is an array of some numeric type (float, double, int, etc).
nent is an integer indicating how many elements are in bonusscores.
Also assuming that the array is 0 based, so legal subscripts range from 0 to nent-1.
// Code starts here
for(int x = 0; x < (nent-1); ++x) {
bonusscores[x] = bonusscores[x] + bonusscores[x+1];
}
// Code ends here
Thing to note, since the last element isn't modified, the range for the for loop is reduced by 1 so that every element to actually be modified is visited, but the last element isn't. And since each element after modification isn't needed for future modifications, it's safe to change them in situ.</span>
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The odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is zero (0).
<h3>What are even numbers and odd numbers?</h3>
The even numbers can be found in a list because they are divisible by two and the remainder of this equation is always zero (0).
Conversely, odd numbers are those that cannot be divided exactly into exact entire numbers (e.g., 3, 5, etc).
The odd numbers in a list can be calculated by the equation ON (odd numbers): n/2 × [f + g], where 'f' is the first number and 'g' is the last number.
In conclusion, the odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is 0.
Learn more about odd numbers here:
brainly.com/question/2263958
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