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cupoosta [38]
4 years ago
12

I need to know how to set this problem up. On monday a security guard spent 4.5hours on patrol and 2hours on surveillance.On tue

sday the officer spent 1 hour and 40 minutes on surveillance and 3 hours on patrol. Which day has a greater ratio of time on surveillance to time on patrol. some one said 7hours ans 30min on patrol and 40min on surveillance???
Mathematics
1 answer:
kherson [118]4 years ago
8 0
OK.......

So, 
ON MONDAY:
Time spent on patrol = 4.5 hrs
Time spent on surveillance = 2 hrs

ON TUESDAY:
Time spent on patrol = 3 hrs
Time spent on surveillance = 1 hr 40 min

Now,
The question is asking us the ratio of <u>surveillance to patrol</u><u /> so, the value of surveillance needs to be on the top.

So,
Let's first change all the units to common units.....i.e. either hrs. to minutes or minutes to hrs.

In this case  .....i think it will be easier to convert minutes to hrs.. because if we do that ...we only have to do one conversion.

So,
1 hr. 40 minuter = 1hr + (40 /60) hrs
                        = 1 + 0.67 
                        = 1.67 hrs

So,
ON TUESDAY:
Time spent on surveillance  = 1.67 hrs

Now,
Let us find the ratio of surveillance to patrol on both days:

ON MONDAY:
Ratio of surveillance to patrol = \frac{2}{4.5}=.44444444444

ON TUESDAY:
Ratio of surveillance to patrol = \frac{1.67}{3}=.556666667

Now,
If we look at the ratio, the ratio of TUESDAY sure is greater than ratio on MONDAY
<u>
</u><u>So, Tuesday has a greater ratio of time on surveillance to time on patrol</u>




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