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svetlana [45]
2 years ago
13

Divide. 8 2/5 ÷ (−2 1/5) Enter your answer as a mixed number, in simplified form, in the box.

Mathematics
1 answer:
koban [17]2 years ago
7 0

Answer:

3 45/55 or 3 9/11

Step-by-step explanation:

convert each term to an improper fraction

42/5 divided by -11/5

dividing fractions is the same as multiply by reciprocal of the second term

42/5 x -5/11 = -210/55

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snow_tiger [21]

Answer:

Step-by-step explanation:

the answer is D. 6 ≤ x < ∞

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2 years ago
Find the value of each variable in the given parallelogram
never [62]

Answer:

I cant see it

Step-by-step explanation:

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3 years ago
this week Rajiv's puppy weighs 8 kilograms. Last week the puppy weighed 6.5 kilograms how much mass in grams did the puppy gains
Olegator [25]

Answer:

1,500 G

Step-by-step explanation:

1 Kilogram (Kg) = 1,000 Grams (G)

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3 0
2 years ago
The perimeter of a rectangular flower garden is 66m and its area is 272m^2. Find the length of the garden.
ExtremeBDS [4]
So we have lengths a and b and are given:

2a+2b = 66 => a+b = 33 => a= 33-b
a*b = 272

plug in one into the other:

(33-b)b = 272 => -b^2 +33b - 272 = 0

Can be factored as (b-16)(b-17) = 0, if you don't "see" this immediately, use the well known abc formula to find b.

So a=16 and b=17 or vice versa.


6 0
2 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

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giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
3 years ago
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