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alukav5142 [94]
2 years ago
12

7. Considere un sistema que contiene un mol de un gas monoatómico retenidito por un pistón. ¿Cuál es el cambio de energía intern

a del gas, Q: 40?0J y W: 200.0J?
Biology
1 answer:
weqwewe [10]2 years ago
4 0

Un mol de un gas monoatómico cuyo calor absorbido es 40.0 J y cuyo trabajo recibido es 200.0 J experimenta un cambio de energía interna de 240.0 J.

Tenemos un mol de un gas monoatómico en un recipiente con un pistón y suceden las siguientes transferencias de energía:

  • El gas absorbe 40.0 J de calor, ya que Q > 0.
  • El gas recibe 200.0 J de trabajo, ya que Q > 0.

Podemos calcular el cambio de energía interna del gas (ΔU) usando la siguiente fórmula.

\Delta U = Q + W = 40.0 J + 200.0 J = 240.0 J

Un mol de un gas monoatómico cuyo calor absorbido es 40.0 J y cuyo trabajo recibido es 200.0 J experimenta un cambio de energía interna de 240.0 J.

Aprende mas: brainly.com/question/21913262

<em>7. Considere un sistema que contiene un mol de un gas monoatómico retenidito por un pistón. ¿Cuál es el cambio de energía interna del gas, Q: 40.0 J y W: 200.0J?</em>

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C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.

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The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.

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