The true statement about the Clayton Act is that: C) the Clayton Act allows a plaintiff to collect three times the damages suffered.
<h3>What is the Clayton Act?</h3>
The Clayton Act is an antitrust law of the United States of America which was enacted by the U.S Congress in the year, 1914 and signed into law by President Woodrow Wilson on the 15th of October, 1914, so as to regulate the behavior or activities of massive business entities.
Basically, the true statement about the Clayton Act is that the Clayton Act allows a plaintiff to demand and collect triple the damages suffered.
Read more on Clayton Act here: brainly.com/question/17083594
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Complete Question:
Which of the following is true of the Clayton Act?
A) The Clayton Act permits price fixing.
B) The Clayton Act allows companies to extend their monopoly power.
C) The Clayton Act allows a plaintiff to collect three times the damages suffered.
D) The original Clayton Act contained sanctions for forfeiture of property.
E) The original Clayton Act did not allow individuals to obtain injunctive relief.
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![\huge \boxed{\mathbb{QUESTION} \downarrow}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cboxed%7B%5Cmathbb%7BQUESTION%7D%20%5Cdownarrow%7D)
Factor the expression into an equivalent form 12y² - 75.
![\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cboxed%7B%5Cmathfrak%7BAnswer%20%5C%3A%20with%20%5C%3A%20Explanation%7D%20%5Cdownarrow%7D)
![12 y ^ { 2 } - 75](https://tex.z-dn.net/?f=12%20y%20%5E%20%7B%202%20%7D%20-%2075)
By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.
![12 y ^ { 2 } - 75 \\ = 3\left(4y^{2}-25\right)](https://tex.z-dn.net/?f=12%20y%20%5E%20%7B%202%20%7D%20-%2075%20%5C%5C%20%20%3D%203%5Cleft%284y%5E%7B2%7D-25%5Cright%29%20)
Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,
- a² = 4, a = 2 (√a² = ✓4 = 2)
- b² = 25, b = 5 (√b² = ✓25 = 5)
So, the (4y² + 25) becomes...
![(4 {y}^{2} - 25) \\ = \left(2y-5\right)\left(2y+5\right)](https://tex.z-dn.net/?f=%284%20%7By%7D%5E%7B2%7D%20%20-%2025%29%20%5C%5C%20%20%3D%20%5Cleft%282y-5%5Cright%29%5Cleft%282y%2B5%5Cright%29%20)
Now, bring the 3 (common factor) & rewrite the complete expression.
![12 y ^ { 2 } - 75 \\ = \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}](https://tex.z-dn.net/?f=12%20y%20%5E%20%7B%202%20%7D%20-%2075%20%5C%5C%20%20%3D%20%20%5Cboxed%7B%20%5Cboxed%7B%20%5Cbf%20%5C%3A%203%5Cleft%282y-5%5Cright%29%5Cleft%282y%2B5%5Cright%29%20%7D%7D)
We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.
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